[PYTHON] file name. You can have a half-width space in pathlib, but you should escape the half-width space when you hit it in the subprocess. If you use check_output, you don't need to escape.

--I want to load csv. --Character code varies depending on the file --There is ␣ in the file name

Story of time

import pathlib
import subprocess as sp

path_file = pathlib.Path('hoge hoge.csv')

encoding = sp.getoutput('nkf -g ' + str(path_file))
df = pd.read_csv(path_file, encoding=encoding)

Anyway, there is an error in the subprocess

import pathlib
import subprocess as sp

path_file = pathlib.Path('hoge\ hoge.csv')

encoding = sp.getoutput('nkf -g ' + str(path_file))
df = pd.read_csv(path_file, encoding=encoding)

(The space between hoge and hoge is \ ␣) Anyway, there is an error in pd.read_csv

Angry! !! !! !! !!

Solved by hard-coding anger (although not so hard)

import pathlib
import subprocess as sp

path_file = pathlib.Path('hoge hoge.csv')

encoding = sp.getoutput('nkf -g ' + str(path_file).replace(' ', '\ ')))
df = pd.read_csv(path_file, encoding=encoding)

I just replaced ␣ with \ ␣.

can not forgive…! Why is there a ␣ in the folder name that the system automatically puts in? I ... I want to erase ␣, which is confused in all file names, before I am born. With this hand, ␣, which is confused with all the file names of all universes, past and future.

Postscript (2017/06/01 17:50) With reference to @ shiracamus's comment encoding = sp.check_output(['nkf', '-g', str(path_file)]) If so, it worked.

I can't tell the difference between get output and check_output by reading the documentation ... I don't have enough study.